x^(2/5)-x^(1/5)-12=0

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Solution for x^(2/5)-x^(1/5)-12=0 equation: 


x in (-oo:+oo)

x^(2/5)-x^(1/5)-12 = 0

t_1 = x^(1/5)

1*t_1^2-1*t_1^1-12 = 0

t_1^2-t_1-12 = 0

DELTA = (-1)^2-(-12*1*4)

DELTA = 49

DELTA > 0

t_1 = (49^(1/2)+1)/(1*2) or t_1 = (1-49^(1/2))/(1*2)

t_1 = 4 or t_1 = -3

t_1 = -3

x^(1/5)+3 = 0

1*x^(1/5) = -3 // : 1

x^(1/5) = -3

( -3 < 0 i 1/5 in (0:1) ) => x naleu017Cy do O

t_1 = 4

x^(1/5)-4 = 0

1*x^(1/5) = 4 // : 1

x^(1/5) = 4

x^(1/5) = 4 // ^ 5

x = 1024

x = 1024

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